Question

Что получится Ca²S+K⇄ Ca²S+H³PO4⇄ Ca²S+BaOH2⇄ Ca²S+NaI⇄

Answer 1

1)Ca²S+K⇄(использовать переместительный закон,чтобы изменить порядок членов)=a²cs+k
2)acs+256or
3)a*(acs+2bho)
4)a*(acs+in)

Answer 2

Chemical Equation Transformation

The given chemical equation can be broken down into several steps to determine the products of each reaction. Let's break it down step by step.

Step 1: Ca²S + K⇄ The reaction between calcium sulfide (Ca²S) and potassium (K) can be represented as: ``` Ca²S + 2K → CaS + K₂S ``` The reaction results in the formation of calcium sulfide (CaS) and potassium sulfide (K₂S) [[1]].

Step 2: CaS + H₃PO₄⇄ The reaction between calcium sulfide (CaS) and phosphoric acid (H₃PO₄) can be represented as: ``` CaS + 2H₃PO₄ → Ca(H₂PO₄)₂ + H₂S ``` The reaction results in the formation of calcium dihydrogen phosphate (Ca(H₂PO₄)₂) and hydrogen sulfide (H₂S) [[2]].

Step 3: Ca(H₂PO₄)₂ + Ba(OH)₂⇄ The reaction between calcium dihydrogen phosphate (Ca(H₂PO₄)₂) and barium hydroxide (Ba(OH)₂) can be represented as: ``` Ca(H₂PO₄)₂ + 2Ba(OH)₂ → 2Ca(OH)₂ + Ba₃(PO₄)₂ ``` The reaction results in the formation of calcium hydroxide (Ca(OH)₂) and barium phosphate (Ba₃(PO₄)₂) [[3]].

Step 4: Ca(OH)₂ + NaI⇄ The reaction between calcium hydroxide (Ca(OH)₂) and sodium iodide (NaI) can be represented as: ``` Ca(OH)₂ + 2NaI → CaI₂ + 2NaOH ``` The reaction results in the formation of calcium iodide (CaI₂) and sodium hydroxide (NaOH) [[4]].

Conclusion

The overall transformation of the given chemical equation results in the formation of calcium sulfide (CaS), potassium sulfide (K₂S), calcium dihydrogen phosphate (Ca(H₂PO₄)₂), hydrogen sulfide (H₂S), barium phosphate (Ba₃(PO₄)₂), calcium hydroxide (Ca(OH)₂), sodium iodide (NaI), calcium iodide (CaI₂), and sodium hydroxide (NaOH). Each step represents a specific chemical reaction and the resulting products.