Question

What is the mass of 11,5 moles of potassium hydroxide ( КОН)? ПОМОГИТЕ. ПОМОГИТЕ.ПОМОГИТЕ.ПОМОГИТЕХИМИЯ ХИМИЯ ХИМИЯСРОЧНО СРОЧНО СРОЧНОдаю 10 баллл​

Answer 1

Ответ:

m = n×Mr

Mr (KOH) = 39 г/моль + 16 г/моль + 1 г/моль = 56 г/моль

m = n×Mr = 11,5 моль × 56 г/моль = 644 г.

Answer 2

The molar mass of potassium hydroxide (KOH) can be calculated by adding the atomic masses of its constituent elements:

• The atomic mass of potassium (K) is approximately 39.10 g/mol.
• The atomic mass of oxygen (O) is approximately 16.00 g/mol.
• The atomic mass of hydrogen (H) is approximately 1.01 g/mol.

Now, we can calculate the molar mass of KOH:

Molar mass of KOH = (1 x K) + (1 x O) + (1 x H) = (1 x 39.10 g/mol) + (1 x 16.00 g/mol) + (1 x 1.01 g/mol) = 39.10 g/mol + 16.00 g/mol + 1.01 g/mol = 56.11 g/mol

So, the molar mass of potassium hydroxide (KOH) is approximately 56.11 g/mol.

Now, to find the mass of 11.5 moles of KOH, you can use the following formula:

Mass (g) = Moles x Molar mass

Mass (g) = 11.5 moles x 56.11 g/mol ≈ 645.165 g

Therefore, the mass of 11.5 moles of potassium hydroxide (KOH) is approximately 645.165 grams.