Question

Fe(OH)3+Fe4[Fe(CN)6]3->?

Answer 1

Ответ:

4Fe(OH)3 + 3K4(Fe(CN)6) → Fe4(Fe(CN)6)3 + 12KOH

Объяснение:

Answer 2

The given chemical equation represents a redox reaction between iron(III) hydroxide (Fe(OH)3) and ferric hexacyanoferrate(III) ([Fe(CN)6]3-). To determine the products of this reaction, we need to balance the equation.

First, let's balance the atoms other than hydrogen (H) and oxygen (O). We have:

Fe(OH)3 + Fe4[Fe(CN)6]3- → ...

Looking at the reactants, we have one iron (Fe) atom on the left side and four on the right side. To balance the number of Fe atoms, we'll place a coefficient of 4 in front of Fe(OH)3:

4Fe(OH)3 + Fe4[Fe(CN)6]3- → ...

Next, let's balance the cyanide (CN-) and hydroxide (OH-) ions. On the left side, we have three OH- ions, so we'll need three H2O molecules to balance them:

4Fe(OH)3 + Fe4[Fe(CN)6]3- → ... + 3H2O

Now let's focus on balancing the CN- ions. On the right side, we have six CN- ions within the complex ion [Fe(CN)6]3-. Therefore, we'll need six Fe(CN)6 units on the left side to balance them:

4Fe(OH)3 + 6Fe4[Fe(CN)6]3- → ... + 3H2O

Finally, we'll balance the charge by adding electrons (e-) to the appropriate side. On the right side, the complex ion [Fe(CN)6]3- has a charge of 3-, so we'll need three electrons on the left side to balance it:

4Fe(OH)3 + 6Fe4[Fe(CN)6]3- → 4Fe(OH)3 + 6Fe4[Fe(CN)6]3- + 3H2O + 3e-

Now the equation is balanced. The products of this reaction are 4 Fe(OH)3, 6 Fe4[Fe(CN)6]3-, 3 H2O, and 3 electrons (e-).