Question

1 mr(P2 O5) =2 mr(Na OH) =3 mr( H2 SO4) =4 mr(Na Cl) =

Answer 1

1) Mr(P2 O5) = 31*2 + 16*5= 142
2) Mr(Na OH) = 23+16+1= 40
3) Mr(H2 SO4) = 1*2+32+16*4= 98
4) Mr(Na Cl) = 23+35.5= 58.5

Answer 2

The molar ratios between the given compounds can be used to calculate the relative quantities of each compound in a chemical reaction involving them. Based on the given information, we can set up the following relationships:

1 mole of P2O5 = 2 moles of NaOH 1 mole of P2O5 = 3 moles of H2SO4 1 mole of P2O5 = 4 moles of NaCl

Since the molar ratios are all based on 1 mole of P2O5, we can set up a system of equations to solve for the relative quantities of each compound in terms of a common variable, x:

x moles of P2O5 = 2x moles of NaOH x moles of P2O5 = 3x moles of H2SO4 x moles of P2O5 = 4x moles of NaCl

Since the total number of moles must be conserved in a chemical reaction, we can set up the following equation:

x + 2x + 3x + 4x = 10x = total number of moles

Solving for x, we get:

x = total number of moles / 10

Now, we can use this value of x to calculate the relative quantities of each compound:

1 mole of P2O5 = x moles 2 moles of NaOH = 2x moles 3 moles of H2SO4 = 3x moles 4 moles of NaCl = 4x moles

For example, if the total number of moles is 10, then:

1 mole of P2O5 = 1 mole 2 moles of NaOH = 2 moles 3 moles of H2SO4 = 3 moles 4 moles of NaCl = 4 moles

Note that the actual quantities of each compound will depend on the specific chemical reaction and the amounts of reactants used.