Question

П(C3H8)=4моль. V-(Co2)-?

Answer 1

С3Н8+5О2=3СО2 + 4Н2О

По уравнению видно, из 1 моль С3Н8 образуется 3 моль СО2, значит из 4 моль ----  n(CO2)=4*3=12 моль

Находим объем СО2

V=n*Vm=12*22,4=268,8 л

Answer 2

To determine the volume of carbon dioxide (CO2) produced from the combustion of 4 moles of propane (C3H8), we need to use the balanced chemical equation for the combustion reaction. The balanced equation is as follows:

C3H8 + 5O2 -> 3CO2 + 4H2O

From the equation, we can see that 1 mole of propane (C3H8) reacts to produce 3 moles of carbon dioxide (CO2). Therefore, if we have 4 moles of propane, we will produce:

4 moles C3H8 * (3 moles CO2 / 1 mole C3H8) = 12 moles CO2

So, the combustion of 4 moles of propane will produce 12 moles of carbon dioxide. The volume of carbon dioxide will depend on the conditions (temperature and pressure) under which the reaction takes place.