Question

Фрагмент молекулы ДНК состоит из 5760 нуклеотидов, из них 1125 тимидиловых нуклеотидов. Определите количество адениловых, гуаниловых и цитидиловых нуклеотидов в данном фрагменте молекулы ДНК.

Answer 1

Дано:
5760 нуклеотидов-всего;
Т - 1125 нуклеотидов.
Найти:
А-? , Г-? , Ц-?
Решение:
По принципу комплементарности (А=Т, Г≡Ц):
1)А+Т=1125+1125=2250 нуклеотидов
Из общего кол-ва вычитаем количество А+Т:
2)5760-2250=3510 нуклеотидов(Г+Ц)
Так как Г≡Ц, то
3510 : 2 = 1755 (кол-во Ц отдельно..Кол-во Г отдельно)
Ответ: А=1125, Г= 1755, Ц= 1755

Answer 2

Calculating the Number of Adenine, Guanine, and Cytosine Nucleotides in the DNA Fragment

The given fragment of DNA consists of 5760 nucleotides, with 1125 of them being thymidine nucleotides. We need to determine the number of adenine, guanine, and cytidine nucleotides in this fragment.

To calculate the number of adenine, guanine, and cytidine nucleotides, we can use the following approach:

1. Calculate the number of thymidine nucleotides: - The given fragment contains 1125 thymidine nucleotides.

2. Calculate the number of non-thymidine nucleotides: - Subtract the number of thymidine nucleotides from the total number of nucleotides: - 5760 - 1125 = 4635 non-thymidine nucleotides.

3. Determine the number of adenine, guanine, and cytidine nucleotides: - Since DNA is a double-stranded molecule, the number of adenine nucleotides is equal to the number of thymidine nucleotides, and the number of guanine nucleotides is equal to the number of cytidine nucleotides. - Therefore, the number of adenine nucleotides is 1125, and the number of guanine and cytidine nucleotides is 4635 / 2 = 2317.5, which can be rounded to 2318 for each.

In summary, the given fragment of the DNA molecule consists of: - Adenine nucleotides: 1125 - Guanine nucleotides: 2318 - Cytidine nucleotides: 2318