Question

Помогите пожалуйста, задача по биологии! Фокстер'єри, гомозиготні за рецесивним алелем певного гена, сліпі від народження. Пара плідників з нормальним фенотипом дала сім цуценят, з яких п'ять мали нормальний фенотип, а двоє виявилися сліпими. встановіть генотипи батьків та їхніх нащадків.

Answer 1

Дано: 
А - норма
а - слепота
_____________
р-?
F1-?
_________________
Решение:
р Аа × Аа
G А а   А а
F1  АА(зрячий), Аа(зрячий), Аа(зрячий), аа(слепой)
Ответ: р: Аа, Аа; F1: АА, Аа, Аа, аа.

Answer 2

Task Analysis

To solve this biology problem, we need to determine the genotypes of the parents and their offspring based on the given information about the inheritance of a recessive allele for blindness in Fox Terriers.

Solution

The parents are both carriers of the recessive allele for blindness, and the offspring include both carriers and non-carriers of the allele.

1. Genotypes of the Parents: - Both parents are carriers of the recessive allele for blindness. - The genotype of each parent is likely to be heterozygous for the blindness allele.

2. Genotypes of the Offspring: - The offspring include both carriers and non-carriers of the recessive allele for blindness. - The genotypes of the offspring can be determined based on the Punnett square analysis.

3. Punnett Square Analysis: - We can use a Punnett square to determine the genotypes of the offspring and infer the genotypes of the parents.

4. Inference: - From the given information, it can be inferred that the genotypes of the parents are likely to be heterozygous for the recessive allele for blindness.

Conclusion

Based on the given information, the genotypes of the parents are likely to be heterozygous for the recessive allele for blindness, and the genotypes of the offspring can be inferred using Punnett square analysis.