Question

У человека отсутствие малых коренных зубов и шестипалость являются доминантными по отношению к норме. Мужчина с шестипалостью и отсутствием малых коренных зубов, гетрозигоиный по обоим вышеупомянутым признаком вступает в брак с женщиной нормальной по этим признакам. Сколько типов гомет у женщины?

Answer 1

А - отсутствие зубов
а - норма
В - шестипалость
в - норма

Генотип женщины: аавв
Её гаметы: ав (т.е. один тип)

Answer 2

Types of Homozygotes in Women

In the given scenario, a man with six fingers and absence of small permanent teeth (small deciduous teeth) is heterozygous for both traits. He marries a woman who is normal for both traits. The question asks how many types of homozygotes exist in women.

To answer this question, we need to consider the inheritance patterns of the traits in question. If the absence of small permanent teeth and six fingers are both dominant traits, then the man must have one dominant allele and one recessive allele for each trait. The woman, being normal for both traits, must have two recessive alleles for each trait.

Based on this information, we can determine the possible types of homozygotes in women. Since the woman is normal for both traits, she must have two recessive alleles for each trait. Therefore, there is only one type of homozygote in women for each trait.

In summary, the woman in this scenario has one type of homozygote for each trait, as she is normal for both traits.

Please note that the information provided is based on the assumption that the absence of small permanent teeth and six fingers are both dominant traits. If there are different inheritance patterns for these traits, the number of homozygotes in women may vary.