Question

Задача. Чтоб правильно было записано дано, решение и ответ. Пожалуйста. У кур ген розовидного гребня доминирует над простым гребнем. Гомозиготного петуха с розовидным гребнем скрестили с гетерозиготной курицей, имеющей розовидный гребень; а) определите сколько типов гамет образуется у самки; б) определите сколько типов гамет образуется у самца; в) определите генотип и фенотип F1; г) какова вероятность ( в % ) появления в F1цыплят с простым гребнем.

Answer 1

Дано:А-розовидный гребень;а-простой гребень. Р: аа x Аа. G: a A,a. F1: Aa aa. ответ:а)2 типа гамет -А и а. б)1 тип гамет-а. в)Генотип-Аа и аа ,фенотип-1-с розовидным гребнем и 1 с простым гребнем; г)50%

Answer 2

Task Analysis:

To answer this task, we need to determine the number of gamete types produced by the female, the number of gamete types produced by the male, the genotype and phenotype of the F1 generation, and the probability of chicks with a simple comb appearing in the F1 generation.

Solution:

a) To determine the number of gamete types produced by the female, we need to consider the genotype of the female. The female is heterozygous for the rose comb trait (Rr). In this case, the female can produce two types of gametes: one with the dominant allele (R) and one with the recessive allele (r). Therefore, the female can produce two types of gametes.

b) To determine the number of gamete types produced by the male, we need to consider the genotype of the male. The male is homozygous for the rose comb trait (RR). In this case, the male can only produce one type of gamete, which carries the dominant allele (R). Therefore, the male can produce one type of gamete.

c) To determine the genotype and phenotype of the F1 generation, we need to consider the cross between the male and female. The male has the genotype RR, and the female has the genotype Rr. When these two individuals are crossed, the possible genotypes of the offspring are RR and Rr. However, since the rose comb trait is dominant, the phenotype of all the offspring will be rose comb. Therefore, the genotype of the F1 generation is Rr, and the phenotype is rose comb.

d) To determine the probability of chicks with a simple comb appearing in the F1 generation, we need to consider the genotype of the F1 generation. The F1 generation has the genotype Rr. Since the rose comb trait is dominant, the simple comb trait (rr) will only be expressed if both alleles are recessive. Therefore, the probability of chicks with a simple comb appearing in the F1 generation is 0%.

Please let me know if you need any further clarification or assistance!