Question

Фрагмент правой цепи днк имеет состав ААТ-АЦЦ-ГГТ-ААА-ГТЦ Определить порядок чередования нуклеотидов в левой цепи. Какова длинна данного фрагмента молекулы днк. Найдите% содержание каждого нуклеотида в данном фрагменте

Answer 1

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Объяснение:

Answer 2

Determining the Nucleotide Sequence and Length of the Left DNA Strand

To determine the nucleotide sequence and length of the left DNA strand, we can use the complementary base pairing rule. According to this rule, adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G).

Given the sequence of the right DNA strand as AAT-ATC-CGT-AAA-GTC, we can determine the nucleotide sequence of the left DNA strand by pairing the complementary bases. The complementary bases for each nucleotide are as follows:

- Adenine (A) pairs with thymine (T) - Thymine (T) pairs with adenine (A) - Cytosine (C) pairs with guanine (G) - Guanine (G) pairs with cytosine (C)

Using this information, we can determine the nucleotide sequence of the left DNA strand:

TТА-TАGG-ССА-TТТ-CАG

Now, let's calculate the length of the DNA fragment. The length of a DNA fragment is determined by counting the number of nucleotides it contains. In the given fragment, we have 20 nucleotides, so the length of the DNA fragment is 20.

Determining the Nucleotide Content of the DNA Fragment

To determine the nucleotide content of the DNA fragment, we need to count the number of occurrences of each nucleotide (A, T, C, and G) in the given fragment.

In the fragment AAT-ATC-CGT-AAA-GTC, we can count the number of occurrences of each nucleotide as follows:

- Adenine (A): 6 occurrences - Thymine (T): 4 occurrences - Cytosine (C): 3 occurrences - Guanine (G): 3 occurrences

Therefore, the nucleotide content of the given DNA fragment is as follows:

- Adenine (A): 6/20 = 30% - Thymine (T): 4/20 = 20% - Cytosine (C): 3/20 = 15% - Guanine (G): 3/20 = 15%

Please note that the percentages are calculated by dividing the number of occurrences of each nucleotide by the total number of nucleotides in the fragment (20) and multiplying by 100.