Question

Определите, сколько граммов С3Н6О3 - молочной кислоты образуется из 360 граммов глюкозы при гликолизе ?

Answer 1

Ответ:Запиши уравнение гликолиза;

хим. кол-во=m:M=360:180=2 моль;

составляем пропорцию: 1/2=2/х; х= 4 моль;

n(C3H4O3)= 4моль;

m(C3H4O3)=n*M= 4моль * 88 г/моль= 352 г.

Объяснени

Answer 2

Calculating the Production of Lactic Acid from Glucose in Glycolysis

To determine the amount of lactic acid (C3H6O3) produced from 360 grams of glucose during glycolysis, we can use the chemical equation for the conversion of glucose to lactic acid.

The balanced chemical equation for the conversion of glucose to lactic acid during glycolysis is as follows: C6H12O6 → 2 C3H6O3

This equation shows that 1 molecule of glucose (C6H12O6) is converted into 2 molecules of lactic acid (C3H6O3) during glycolysis.

To calculate the amount of lactic acid produced from 360 grams of glucose, we can use the molar mass of glucose and lactic acid to convert the mass of glucose to moles and then use the mole ratio from the balanced chemical equation to find the moles of lactic acid produced. Finally, we can convert the moles of lactic acid to grams.

Calculation Steps:

1. Calculate the molar mass of glucose (C6H12O6). 2. Convert the mass of glucose to moles. 3. Use the mole ratio from the balanced chemical equation to find the moles of lactic acid produced. 4. Convert the moles of lactic acid to grams.

Calculation:

1. Molar Mass of Glucose (C6H12O6): - The molar mass of glucose (C6H12O6) is calculated as: - Carbon (C): 6 × 12.01 g/mol = 72.06 g/mol - Hydrogen (H): 12 × 1.01 g/mol = 12.12 g/mol - Oxygen (O): 6 × 16.00 g/mol = 96.00 g/mol - Total Molar Mass: 72.06 + 12.12 + 96.00 = 180.18 g/mol

2. Convert Mass of Glucose to Moles: - Moles of Glucose = Mass of Glucose / Molar Mass of Glucose - Moles of Glucose = 360 g / 180.18 g/mol = 1.998 moles

3. Use Mole Ratio to Find Moles of Lactic Acid: - From the balanced chemical equation, 1 mole of glucose produces 2 moles of lactic acid. - Moles of Lactic Acid = Moles of Glucose × 2 - Moles of Lactic Acid = 1.998 moles × 2 = 3.996 moles

4. Convert Moles of Lactic Acid to Grams: - Mass of Lactic Acid = Moles of Lactic Acid × Molar Mass of Lactic Acid - Molar Mass of Lactic Acid (C3H6O3): - Carbon (C): 3 × 12.01 g/mol = 36.03 g/mol - Hydrogen (H): 6 × 1.01 g/mol = 6.06 g/mol - Oxygen (O): 3 × 16.00 g/mol = 48.00 g/mol - Total Molar Mass: 36.03 + 6.06 + 48.00 = 90.09 g/mol - Mass of Lactic Acid = 3.996 moles × 90.09 g/mol = 359.64 grams

Answer:

Therefore, 360 grams of glucose would produce approximately 359.64 grams of lactic acid during glycolysis.

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