Question

4. Периметр прямокутника дорівнює 20 см. Знайдіть його сторони, якщо одна з них на 2 см менша за другу.​

Answer 1

Ответ:

4, 6 см

Объяснение:

Напівпериметр прямокутника р=20:2=10 см.

Нехай ширина а=х см, тоді довжина в=х+2 см.

х+х+2=10; 2х=8; х=4.

а=4 см; в=9+2=6 см.

Відповідь: 4 см, 6 см.

Answer 2

Finding the Sides of a Rectangle with a Given Perimeter

To find the sides of a rectangle when the perimeter is given, we can use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (Length + Width)

In this case, we are given that the perimeter of the rectangle is 20 cm, and one of the sides is 2 cm less than the other side. Let's assume that the length of the rectangle is x cm.

According to the given information, the width of the rectangle would be x - 2 cm.

Using the formula for the perimeter, we can set up the equation:

20 = 2 * (x + (x - 2))

Simplifying the equation:

20 = 2 * (2x - 2)

10 = 2x - 2

2x = 10 + 2

2x = 12

x = 12 / 2

x = 6

So, the length of the rectangle is 6 cm, and the width is 6 - 2 = 4 cm.

Therefore, the sides of the rectangle are 6 cm and 4 cm.