Question

) 7(a² + 2) - 4(a + 3)(a - 3) + 3a2 + 24 = 6a2 + 74; ) 10/22 - 15)-121a - 4 a + 4) + 8 - a2 = 50 - 3a2.​

Answer 1

вот так я решил посмотри пожалуйста

Answer 2

To solve the equations, let's simplify and solve each equation separately:

1. $7(a^2 + 2) - 4(a + 3)(a - 3) + 3a^2 + 24 = 6a^2 + 74$

First, let's expand the expressions within parentheses:

$7a^2 + 14 - 4(a^2 - 9) + 3a^2 + 24 = 6a^2 + 74$

Simplify further:

$7a^2 + 14 - 4a^2 + 36 + 3a^2 + 24 = 6a^2 + 74$

Combine like terms:

$6a^2 + 74 = 6a^2 + 74$

The equation simplifies to $6a^2 + 74 = 6a^2 + 74$. This means that the equation is an identity and holds true for all values of $a$. There are infinitely many solutions to this equation.

2. $\frac{{10}}{{22}} - 15 - (-121a - 4a + 4) + 8 - a^2 = 50 - 3a^2$

Simplify and combine like terms:

$\frac{{5}}{{11}} - 15 + 125a - a^2 + 8 - a^2 = 50 - 3a^2$

Rearrange the equation:

$-3a^2 + a^2 + a^2 + 125a + 5 - 15 + 8 = 50$

Combine like terms:

$123a + -2 = 50$

Simplify further:

$123a = 52$

Divide both sides by 123:

$a = \frac{{52}}{{123}}$

So, the solution to the second equation is $a = \frac{{52}}{{123}}$.