Question

(3a/4+5 + 3a-1/5-4a - 25-30a/16a²-25) : 5a-25/25-40a+16a³=​

Answer 1

Ответ:

Прости я учусь в 1 клласе

Объяснение:

Answer 2

Let's simplify the given expression step by step:

(3a/4 + 5 + 3a - 1/5 - 4a - 25 - 30a)/(16a^2 - 25) : (5a - 25)/(25 - 40a + 16a^3)

First, factor the denominators:

The denominator of the left fraction is already factored: 16a^2 - 25 = (4a + 5)(4a - 5).

The denominator of the right fraction is also factored: 25 - 40a + 16a^3 = 5(5 - 8a + 4a^3).

Now, let's rewrite the expression:

[(3a/4 + 5 + 3a - 1/5 - 4a - 25 - 30a)/(4a + 5)(4a - 5)] : [(5a - 25)/5(5 - 8a + 4a^3)]

Next, let's simplify the numerators and denominators individually:

Numerator of the left fraction: 3a/4 - 1/5 - 4a - 30a + 5 - 25 Combine like terms: (3a - 120a)/4 - (1/5) + 5 - 25 -117a/4 - 1/5 - 20

Numerator of the right fraction: 5a - 25

Now, the expression becomes:

[(-117a/4 - 1/5 - 20)/(4a + 5)(4a - 5)] : [(5a - 25)/5(5 - 8a + 4a^3)]

Now, let's simplify the entire expression by multiplying the left fraction by the reciprocal of the right fraction:

[(-117a/4 - 1/5 - 20)/(4a + 5)(4a - 5)] * [(5(5 - 8a + 4a^3))/(5a - 25)]

Now, we can cancel common factors between the numerators and denominators:

[-117a/4 - 1/5 - 20] * [(5 - 8a + 4a^3)] / [(4a + 5)(4a - 5)(5)]

Now, let's simplify further:

[-117a/4 - 1/5 - 20] * [(5 - 8a + 4a^3)] / [20a^2 - 25(4a + 5)]

Now, let's factor out a -1 from the first term in the numerator:

[-(117a/4 + 1/5 + 20)] * [(5 - 8a + 4a^3)] / [20a^2 - 25(4a + 5)]

Now, let's simplify further:

[-(117a/4 + 1/5 + 100/5)] * [(5 - 8a + 4a^3)] / [20a^2 - 100a - 125]

Now, we can simplify the constants in the first term:

[-(117a/4 + 101/5)] * [(5 - 8a + 4a^3)] / [20a^2 - 100a - 125]

This is the simplified expression. If you want to factor or simplify it further, please let me know.