Question

Определить эквивалентное сопротивление четырёх резисторов соединенных последовательно, если R1=4 Ом R2=6 Ом R3=8Ом R4=24 Ом И ПЛЮС СХЕМА

Answer 1

Эквивалентное сопротивление в последовательном соединении равна сумме сопротивлений отдельных резисторов,то-есть,
Rобщ=R1+R2+R3+R4=4Ом+6Ом+8Ом+24Ом=42 Ом

Answer 2

Calculating Equivalent Resistance of Resistors in Series

To calculate the equivalent resistance of resistors connected in series, you simply add up the individual resistances. Given the resistances R1=4 Ω, R2=6 Ω, R3=8 Ω, and R4=24 Ω, the equivalent resistance (R_eq) can be calculated as:

R_eq = R1 + R2 + R3 + R4

Substituting the given values:

R_eq = 4 Ω + 6 Ω + 8 Ω + 24 Ω

R_eq = 42 Ω

So, the equivalent resistance of the four resistors connected in series is 42 Ω.

Circuit Diagram

Unfortunately, I'm unable to provide a circuit diagram at the moment. However, you can visualize the resistors connected in series as follows:

----[R1=4Ω]----[R2=6Ω]----[R3=8Ω]----[R4=24Ω]----

This represents the four resistors (R1, R2, R3, R4) connected in series.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.