Question

13-y2=0 ; x2-10x+24=0.​

Answer 1

13-2y=0 2x-10x+24=0
-2y= 0-13. 2x-10x= 0-24
-2y=-13. -12x=-24
y= + 6,5. x= +2

Answer 2

It seems like you have provided two equations:

1. $13 - y^2 = 0$
2. $x^2 - 10x + 24 = 0$

It looks like you want to solve for the variables $x$ and $y$ in these equations. Let's solve them one by one:

Equation 1: $13 - y^2 = 0$

To solve for $y$, we can isolate $y^2$ on one side of the equation:

$y^2 = 13$

Now, take the square root of both sides:

$y = \pm \sqrt{13}$

So, the solutions for $y$ are $y = \sqrt{13}$ and $y = -\sqrt{13}$.

Equation 2: $x^2 - 10x + 24 = 0$

To solve for $x$, we can factor the quadratic equation:

$x^2 - 10x + 24 = (x - 6)(x - 4) = 0$

Now, set each factor equal to zero and solve for $x$:

$x - 6 = 0$ --> $x = 6$

$x - 4 = 0$ --> $x = 4$

So, the solutions for $x$ are $x = 6$ and $x = 4$.

In summary, the solutions for the given equations are:

For the first equation: $y = \sqrt{13}$ and $y = -\sqrt{13}$ For the second equation: $x = 6$ and $x = 4$.