Question

90 + 10lg10= Определение сумарного шума при работе нескольких источников

Answer 1

90 + 10lg10 = 90+10*1 = 100(lg10=1).

Answer 2

It seems there might be some confusion in the equation you provided. The expression "90 + 10lg10" doesn't directly relate to determining the total noise in multiple sources. However, I can help you understand how to calculate the total noise when multiple sources are involved.

To determine the total noise when multiple sources are operating simultaneously, you need to consider each noise source separately and then combine their contributions. The formula for combining noise power levels is as follows:

Total Noise (in dB) = 10 * log10(Sum of (10^(Individual Noise/10)))

Here's how you can use this formula:

1. Measure or estimate the noise power (in dB) of each individual noise source separately.
2. Convert the individual noise power values to linear scale by taking the antilog (i.e., raising 10 to the power of the individual noise value divided by 10).
3. Sum up the linear scale noise values from all the sources.
4. Convert the sum back to dB scale by taking the logarithm (base 10) of the sum.
5. The result will give you the total noise in dB when all the sources are active.

Keep in mind that noise power levels add up logarithmically because noise is usually represented on a logarithmic scale (in dB). Adding noise levels in a linear fashion would not accurately represent the total noise.

Remember that this formula assumes that the noise sources are uncorrelated. If the sources are correlated, additional considerations may be needed in the calculation.