Question

Massasi 66g bo'lgan K4P2O7 dagi kaliy atomlar miqdorini aniqlang

Answer 1

K4P2O7 is the chemical formula for potassium pyrophosphate. To determine the quantity of potassium atoms in 66g of K4P2O7, we need to calculate the molar mass of K4P2O7 and then use it to convert the given mass to moles. Finally, we can multiply the number of moles by Avogadro's number to find the quantity of potassium atoms.

Calculating the molar mass of K4P2O7:

The molar mass of an element or compound is the mass of one mole of that substance. To calculate the molar mass of K4P2O7, we need to sum up the atomic masses of all the atoms in the compound.

The atomic masses of the elements involved are: - Potassium (K): 39.10 g/mol - Phosphorus (P): 30.97 g/mol - Oxygen (O): 16.00 g/mol

The subscripts in the chemical formula indicate the number of atoms of each element in one molecule of the compound. In K4P2O7, there are 4 potassium atoms, 2 phosphorus atoms, and 7 oxygen atoms.

Using these values, we can calculate the molar mass of K4P2O7 as follows: (4 * 39.10 g/mol) + (2 * 30.97 g/mol) + (7 * 16.00 g/mol) = 330.22 g/mol

Converting mass to moles:

To convert the given mass of 66g to moles, we divide the mass by the molar mass: 66g / 330.22 g/mol = 0.1999 mol (rounded to four decimal places)

Calculating the quantity of potassium atoms:

Since there are 4 potassium atoms in one molecule of K4P2O7, the number of moles of potassium atoms is also 0.1999 mol.

To find the quantity of potassium atoms, we multiply the number of moles by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol: 0.1999 mol * (6.022 x 10^23 atoms/mol) = 1.202 x 10^23 potassium atoms

Therefore, there are approximately 1.202 x 10^23 potassium atoms in 66g of K4P2O7.

Please note that the calculations provided are based on the given information and assumptions about the compound's purity and stoichiometry.