Question

1. y=3-x2. y=0,5x-23. y=2/7x-24. y=-3

Answer 1

Вот как бы да
держи

Answer 2

To solve this system of equations, we can use substitution or elimination methods.

Using substitution method:

From the first equation, we can rearrange to get x^2 = 3 - y. Substituting this into the second equation, we get:

0.5x - 23 = y

0.5x - 23 = x^2 - 3

Rearranging, we get:

x^2 - 0.5x - 20 = 0

Using the quadratic formula, we get:

x = (0.5 ± √(0.5^2 + 4(1)(20))) / 2 x = 5 or x = -4

Substituting these values into the first equation to get the corresponding y-values, we get:

When x = 5, y = 3 - (5^2) = -22 When x = -4, y = 3 - (-4^2) = -13

So the solutions to the system of equations are (5, -22) and (-4, -13).

Using elimination method:

We can rewrite the second and third equations as:

2x/7 - y = 24 2x/7 - 5y/2 = 115/2

Multiplying the first equation by 5 and subtracting it from the second equation, we get:

-23x/14 = -23/2

Solving for x, we get:

x = 7

Substituting this value into the first equation to get the corresponding y-value, we get:

y = 3 - (7^2) = -44

So the solution to the system of equations is (7, -44).