Question

1) y-2x+1=0 2) X-y-2=03) 2x + 2-24 =0") 24-4x+6=0X Х.C5) 5x+3-y=ub) 24-5x +6=07) 4-3x-2y=0 Пажалуста ​

Answer 1

5 5 1 5 5 2.....

..........

Answer 2

It looks like you've provided a set of linear equations. To solve a system of linear equations, you can use various methods such as substitution, elimination, or matrices. Let's solve the system of equations you've given:

1. $y - 2x + 1 = 0$
2. $x - y - 2 = 0$
3. $2x + 2 - 24 = 0$
4. $24 - 4x + 6 = 0$
5. $5x + 3 - y = 0$
6. $24 - 5x + 6 = 0$
7. $4 - 3x - 2y = 0$

I'll go through the solution step by step:

1. From equation (3), simplify it: $2x - 22 = 0$, which gives $x = 11$.
2. Substitute $x = 11$ into equation (4): $24 - 4(11) + 6 = 0$, which simplifies to $2 = 0$. This means there is no solution, as the equation is inconsistent.
3. Substitute $x = 11$ into equation (5): $5(11) + 3 - y = 0$, which simplifies to $y = 58$.
4. Substitute $x = 11$ and $y = 58$ into equation (2) to check: $11 - 58 - 2 = -49 \neq 0$. This system is inconsistent.

Therefore, the system of equations you provided does not have a solution that satisfies all the equations simultaneously. If you have any additional information or if there is a mistake in the equations, please double-check and provide the correct information.