Question

Определите атмосферное давление на вершине холмавысотой 50 м., если у его подножия оно составляет 750мм.рт.ст.

Answer 1

На каждие 100метров а.т. понижаєтся на 10мм рт ст
50метров=5мм рт ст
750-5=645мм рт ст

Answer 2

Calculating Atmospheric Pressure at the Top of the Hill

To calculate the atmospheric pressure at the top of the hill, we can use the relationship between atmospheric pressure and height.

Given: - Atmospheric pressure at the base of the hill = 750 mmHg - Height of the hill = 50 m

We can use the following formula to calculate the atmospheric pressure at the top of the hill:

P₂ = P₁ - ρgh

Where: - P₂ = atmospheric pressure at the top of the hill - P₁ = atmospheric pressure at the base of the hill - ρ = density of the fluid (in this case, air) - g = acceleration due to gravity - h = height difference

Calculation

Using the given values: - P₁ = 750 mmHg - h = 50 m

We need to convert the units to be consistent. 1 mmHg is approximately equal to 133.322 Pa.

So, 750 mmHg = 750 * 133.322 Pa = 99991.5 Pa

Now, we can calculate the atmospheric pressure at the top of the hill using the formula:

P₂ = 99991.5 Pa - (1.2 kg/m³ * 9.81 m/s² * 50 m)

Where: - ρ (density of air) = 1.2 kg/m³ - g (acceleration due to gravity) = 9.81 m/s²

Result

Calculating the value: P₂ ≈ 99991.5 Pa - 5886 Pa ≈ 94105.5 Pa

So, the atmospheric pressure at the top of the hill is approximately 94105.5 Pa.