Question

Определите высоту объекта если атмосферное давление на его вершине составило 460 мм рт. ст., а у подножья было 760 мм рт. ст.

Answer 1

Так как, каждые 10, 5 метров вверх атмосферное давление понижается на 1 мм. ртутного столба, то получается:
 1) 760 - 460 = 300 мм. ртутного столба атмосферное давление понизилось
2) 300  * 10,5 = 3150 метров
Ответ: высота объекта составляет 3150 метров

Answer 2

200 метров, так как при подъёме на 1 метр давление уменьшается на 1 мм рт. ст.

Answer 3

Calculating the Height of the Object Based on Atmospheric Pressure

To calculate the height of the object based on the given atmospheric pressures at its top and bottom, we can use the following formula:

h = (RT/g) * ln(P1/P2)

Where: - h = height of the object - R = universal gas constant (8.314 J/(mol·K)) - T = average temperature of the air in Kelvin - g = acceleration due to gravity (9.81 m/s^2) - P1 = pressure at the top of the object - P2 = pressure at the bottom of the object - ln = natural logarithm

Applying the Formula

Given: - Pressure at the top of the object (P1) = 460 mm Hg - Pressure at the bottom of the object (P2) = 760 mm Hg

We can convert the pressures from mm Hg to atm (atmospheres) for the formula: 1 atm = 760 mm Hg

So, P1 = 460 mm Hg = 0.6053 atm and P2 = 760 mm Hg = 1 atm

Using the formula, we can calculate the height of the object.

Calculation

Using the formula h = (RT/g) * ln(P1/P2), and substituting the values: - R = 8.314 J/(mol·K) - T = average temperature of the air in Kelvin (not provided) - g = 9.81 m/s^2 - P1 = 0.6053 atm - P2 = 1 atm

We can calculate the height of the object.

Conclusion

The height of the object can be calculated using the given atmospheric pressures at its top and bottom. However, without the average temperature of the air, the exact height cannot be determined. If the average temperature of the air is provided, the height can be accurately calculated using the formula mentioned above.