Question

Высота главного здания МГУ в Москве 237 м .Какова атмосфера давление на его шпиле , если у основания здания оно состовляет 745 мм рт.ст.?

Answer 1

Так как каждые 12 м давление увеличивается на 1 мм рт.ст., то
237/12=19,75
Далее вычитаем из давления у основания здания получившееся значение, так как с увеличением высоты, давление понижается:
745-19,75=725,25

Answer 2

Atmospheric Pressure at the Spire of the Main Building of Moscow State University

The atmospheric pressure at the spire of the main building of Moscow State University can be calculated using the given information.

Given: - Height of the main building of Moscow State University: 237 m - Atmospheric pressure at the base of the building: 745 mm Hg

To calculate the atmospheric pressure at the spire of the building, we can use the relationship between atmospheric pressure and height.

According to the barometric formula, the atmospheric pressure decreases with increasing altitude. The relationship between pressure and height is given by the formula:

P = P₀ * e^(-Mgh/RT)

Where: - P = pressure at height h - P₀ = pressure at the base - M = molar mass of Earth's air - g = acceleration due to gravity - h = height - R = universal gas constant - T = temperature

Using this formula, we can calculate the atmospheric pressure at the spire of the main building of Moscow State University.

Applying the formula with the given values: - P₀ = 745 mm Hg - h = 237 m

Calculation: - M = 0.029 g/mol (molar mass of air) - g = 9.81 m/s² (acceleration due to gravity) - R = 8.314 J/(mol·K) (universal gas constant) - T = Standard temperature (assumed to be 288 K)

Plugging in the values and solving for P:

P = 745 * e^(-0.029 * 9.81 * 237 / (8.314 * 288))

P ≈ 745 * e^(-0.237)

P ≈ 745 * 0.789

P ≈ 588.105 mm Hg

Therefore, the atmospheric pressure at the spire of the main building of Moscow State University is approximately 588.105 mm Hg.

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