Question

Нормальний атмосферний тиск у підніжжі гори 762 мм рт. ст. який атмосферний тиск буде на висоті 17 м

Answer 1

Примерно 760,6
Каждые 12 м подъема уменьшают атмосферное давление на 1 мм.рт.ст
17/12=1,4
762-1,4=760,6

Answer 2

Atmospheric Pressure at Different Altitudes

Atmospheric pressure decreases with increasing altitude. The standard atmospheric pressure at sea level is approximately 1013.25 millibars (or 760 mm Hg). As altitude increases, the atmospheric pressure decreases.

Calculating Atmospheric Pressure at 17 meters

To calculate the atmospheric pressure at a specific altitude, we can use the barometric formula, which describes how pressure decreases with altitude. The formula is:

\[ P = P_0 \times e^{-\frac{M \times g \times h}{R \times T}} \]

Where: - \( P \) = pressure at the given altitude - \( P_0 \) = standard pressure at sea level (1013.25 millibars or 760 mm Hg) - \( M \) = molar mass of Earth's air (approximately 0.029 kg/mol) - \( g \) = acceleration due to gravity (approximately 9.81 m/s²) - \( h \) = height above sea level - \( R \) = universal gas constant (approximately 8.314 J/(mol·K)) - \( T \) = temperature in Kelvin

Calculation

Using the given altitude of 17 meters, we can calculate the atmospheric pressure at this height using the barometric formula.

\[ P = 1013.25 \times e^{-\frac{0.029 \times 9.81 \times 17}{8.314 \times 288}} \]

\[ P \approx 1013.25 \times e^{-\frac{4.802}{8.314}} \]

\[ P \approx 1013.25 \times e^{-0.578} \]

\[ P \approx 1013.25 \times 0.559 \]

\[ P \approx 566.1 \, \text{millibars} \]

Conclusion

At an altitude of 17 meters, the atmospheric pressure is approximately 566.1 millibars.