Question

АВ=EF,CF=AD, CB=DE, угол BCF=85градусов найти угол ADB​

Answer 1

AB=EF

AD=CF

EB-общая, значит треугольник BAD = треугольнику EFC

угол BCF=85 градусов

углы BCF и   ECF смежныеи их сумма = 180 градусов,

тогда угол ECF=180-85=95 градусов

Так как треугольники равны, то угол ECF соответствует ( равен ) углу ADB,

Значит угол ADB=95 г.

Ответ: 95 градусов

Answer 2

Ответ:

расписала очень подробно,надеюсь еще не поздно

Answer 3

To find the angle ADB, we can start by drawing a diagram based on the given information. Let's label the points on the diagram as follows:

C |
|
|
B____D | / | / |/ A | E | F

Given: AV = EF CF = AD CB = DE ∠BCF = 85°

We need to find ∠ADB.

Since AV = EF, we can conclude that triangles AEF and AVC are congruent by the side-side-side (SSS) criterion.

Similarly, since CF = AD, triangles CFB and ADB are congruent by the side-side-side (SSS) criterion.

Now, let's look at the triangle ADB:

∠BCF = ∠CBF = 85° (given) ∠BAC = ∠EAF (corresponding angles in congruent triangles) ∠ADB = ∠CFB (corresponding angles in congruent triangles) ∠ADB = ∠BCF = 85°

Therefore, the angle ∠ADB is 85 degrees.