Question

2х - 2y = 1,6ху = 2,4​

Answer 1

Ответ:

у1=-2

у2=1,2

Объяснение:

2(х-у)=1,6

х-у=0,8

ху=2,4

х=у+0,8

(у+0,8)у=2,4

у²+0,8у-2,4=0

(у+2)(у-1,2)=0

у1=-2. у2=1,2

Answer 2

To solve the given system of equations:

1. 2x - 2y = 1
2. 6x - 2y = 2.4

We can use the method of substitution or elimination. Let's solve it using the method of substitution:

From equation 1, we can express x in terms of y: 2x = 2y + 1 x = (2y + 1)/2

Now substitute this value of x into equation 2: 6((2y + 1)/2) - 2y = 2.4 3(2y + 1) - 2y = 2.4 6y + 3 - 2y = 2.4 4y + 3 = 2.4 4y = 2.4 - 3 4y = -0.6 y = -0.6/4 y = -0.15

Now substitute the value of y back into equation 1 to find x: 2x - 2(-0.15) = 1 2x + 0.3 = 1 2x = 1 - 0.3 2x = 0.7 x = 0.7/2 x = 0.35

Therefore, the solution to the given system of equations is: x = 0.35 y = -0.15