Question

164.1. х2+3x-18>03. x-x-1220й. -у10-240)​

Answer 1

Ответ:

Решим полное квадратное уравнение х^​2 + 3х = 18. Преобразуем его — перенесем в левую часть уравнения слагаемое с правой части, получим:

x^2 + 3x - 18 = 0;

Полные квадратные уравнения решаются с помощью нахождения дискриминанта.

Вспомним формулу для его нахождения:

D = b^2 - 4ac;

D = 3^2 - 4 * 1 * (- 18) = 9 + 72 = 81.

Вспомним формулы для нахождения корней квадратного уравнения и найдем корни заданного уравнения:

х1 = (- b + √D)/ 2a = (- 3 + √81)/2 * 1 = (- 3 + 9)/2 = 6/2 = 3.

x2 = (- b - √D)/2a = (- 3 - √81)/2 * 1= (- 3 - 9)/2 = - 12/2 = - 6.

Ответ: х = 3; х = - 6.

Объяснение:

Answer 2

It seems like you've provided an expression, but it's not very clear what you're asking for. It looks like you might want to solve an inequality or equation, but there are some typos and formatting issues in your input. Let's try to clarify and solve the expression:

If your expression is:

164.1x^2 + 3x - 18 > 0

Then, you want to find the values of x for which this inequality is true. To do that, you can factor the quadratic and use the sign of the factors to determine the solution.

1. First, let's factor the quadratic expression:

   164.1x^2 + 3x - 18 = 0

   This quadratic doesn't factor easily, so you can use the quadratic formula to find the roots:

   x = (-b ± √(b² - 4ac)) / (2a)

   where a = 164.1, b = 3, and c = -18.

2. Plug in these values into the quadratic formula:

   x = (-3 ± √(3² - 4 * 164.1 * (-18))) / (2 * 164.1)

3. Calculate the discriminant (the value inside the square root):

   Discriminant = 3² - 4 * 164.1 * (-18)

4. If the discriminant is greater than zero, you will have two real roots. If it's equal to zero, you will have one real root. If it's less than zero, you will have no real roots.

5. Once you have the roots, you can determine the intervals where the inequality is satisfied. For this particular inequality, you want to find where 164.1x^2 + 3x - 18 > 0.

If you could clarify any formatting issues or provide more context, I'd be happy to assist you further.