Question

X2 + 9 < 0;(x + 5)2 + 3 < 0;-(x - 2)2 - 4 > 0.66):25 >2​

Answer 1

Объяснение:

1)2х+9<0 2х<0-9 2х<-9|:2 х<-4.5

2)(х+5)2+3<0 2х+10+3<0 2х<0-10-3 2х<-13|:2 х<-6.5

3) -(х-2)2-4>0 (х+2)2-4>0 2х+4-4>0 2х>0-4+4 2х>0|:2 х>0

Answer 2

Let's solve each inequality step by step:

1. x^2 + 9 < 0: This inequality has no real solutions because the sum of a square and a positive number is always greater than or equal to zero. Therefore, there are no values of x that satisfy this inequality.

2. (x + 5)^2 + 3 < 0: Again, this inequality has no real solutions. The square of any real number, in this case, (x + 5)^2, is always greater than or equal to zero. Adding a positive number (3) to it will only make it greater, so there are no values of x that satisfy this inequality.

3. -(x - 2)^2 - 4 > 0.66: Let's simplify this inequality: -(x - 2)^2 - 4 > 0.66 -(x - 2)^2 > 0.66 + 4 -(x - 2)^2 > 4.66

   To solve this, we need to flip the inequality sign and take the square root of both sides: (x - 2)^2 < -4.66

   Since the square of any real number is always non-negative, there are no real solutions for this inequality.

4. 25 > 2: This inequality is true because 25 is indeed greater than 2.

To summarize:

1. x^2 + 9 < 0 has no real solutions.
2. (x + 5)^2 + 3 < 0 has no real solutions.
3. -(x - 2)^2 - 4 > 0.66 has no real solutions.
4. 25 > 2 is true.