Question

Напишите какая программа для этого в с++ У={х*2-4 при х>0 {2х при х<=0 Это одна система 1 Смотреть ответ MrMiner1 MrMiner1 #include <iostream>using namespace std;int main(){ cout.precision(10); double x, y; cin>>x; if (x>0) y=x*2-4; else y=2*x; cout<<y;}_____Если в первой строке системы x*2 означает x в квадрате, то замените if (x>0) y=x*2-4; на if (x>0) y=x*x-4;

Answer 1

Program for the Given Equation

To write a program for the given equation, we can use the C++ programming language. The equation is defined as follows:

- If x > 0, then y = x*2 - 4. - If x <= 0, then y = 2*x.

Here's an example program that implements this equation:

#include 
using namespace std;

int main() {
    cout.precision(10);
    double x, y;
    cin >> x;
    if (x > 0)
        y = x*2 - 4;
    else
        y = 2*x;
    cout << y;
}

In this program, we first include the necessary header file `iostream` for input/output operations. Then, we declare the variables `x` and `y` as doubles to store the input and output values, respectively.

Next, we use `cin` to read the value of `x` from the user. The `if` statement checks whether `x` is greater than 0. If it is, the equation `y = x*2 - 4` is evaluated and assigned to `y`. Otherwise, if `x` is less than or equal to 0, the equation `y = 2*x` is evaluated and assigned to `y`.

Finally, we use `cout` to display the value of `y` as the output.

If the equation `x*2` represents `x` squared in the first line of the system, you can replace `y = x*2 - 4` with `y = x*x - 4` in the `if` statement.

I hope this helps! Let me know if you have any further questions.