Question

На языке С или С++ . Напишите программу, которая получает день и номер месяца и определяет дату сле-дующего дня. Считайте, что год невисокосный (365 дней). Пример: Введите день и месяц: 25 12 Следующий день: 26 декабря Пример: Введите день и месяц: 28 2 Следующий день: 1 марта

Answer 1

Program in C to Determine the Next Date

Here's a program written in C that takes the day and month as input and determines the date of the next day. It assumes a non-leap year with 365 days.

#include

int main() {
    int day, month;

printf("Enter the day and month: ");
    scanf("%d %d", &day, &month);

// Determine the number of days in each month
    int daysInMonth[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

// Check if the entered day and month are valid
    if (month < 1 || month > 12 || day < 1 || day > daysInMonth[month - 1]) {
        printf("Invalid date!\n");
        return 0;
    }

// Check if it's the last day of the month
    if (day == daysInMonth[month - 1]) {
        // Check if it's the last day of the year
        if (month == 12) {
            day = 1;
            month = 1;
        } else {
            day = 1;
            month++;
        }
    } else {
        day++;
    }

// Print the next date
    printf("Next day: %d ", day);

// Determine the month name based on the month number
    char* monthNames[] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
    printf("%s\n", monthNames[month - 1]);

return 0;
}

This program prompts the user to enter the day and month. It then checks if the entered date is valid. If it is, it determines the next date by incrementing the day. If the day is the last day of the month, it checks if it's the last day of the year. If it is, it sets the day to 1 and increments the month. Finally, it prints the next date in the format "Next day: [day] [month name]".

Example: ``` Enter the day and month: 25 12 Next day: 26 December ```

Enter the day and month: 28 2
Next day: 1 March

Please note that this program assumes the input is valid and does not handle leap years.