Question

ПОМОГИТЕ!!! ОЧЕНЬ НАДО!!!Дано многоразрядное число N<=10^9. Найти среднее арифметическое цифр числа, разряды которых равны 2 и 5. P.S. Я уже задавала эту задачу, но у меня ее не приняли так как нужно через цикл

Answer 1

// счет разрядов от нуля справа налево: ХХХ5ХХ2ХХ
var
  n:longint;
  a,b,k,d:integer;
begin
  Write('Введите натуральное число длиной 6-9 цифр: ');
  Read(n);
  k:=0;
  while n>0 do begin
    d:=n mod 10;
    if k=2 then a:=d
    else
      if k=5 then b:=d;
    Inc(k);
    n:=n div 10
    end;
  Writeln('Ср. арифм. разрядов 2 и 5 равно ',(a+b)/2)
end.

Пример
Введите натуральное число длиной 6-9 цифр: 123456789
Ср. арифм. разрядов 2 и 5 равно 5.5

Answer 2

Problem Analysis

To find the arithmetic mean of the digits in a given multi-digit number, we need to: 1. Extract the individual digits from the number. 2. Calculate the sum of the digits that are equal to 2 or 5. 3. Count the number of digits that are equal to 2 or 5. 4. Divide the sum by the count to find the arithmetic mean.

Solution

Here's a step-by-step solution to find the arithmetic mean of the digits in a given multi-digit number, where the digits are equal to 2 or 5:

1. Convert the given number to a string to easily extract the individual digits. 2. Initialize two variables: `sum` to keep track of the sum of the digits and `count` to keep track of the number of digits that are equal to 2 or 5. 3. Iterate through each character in the string representation of the number. 4. Check if the character is equal to '2' or '5'. If it is, convert it back to an integer and add it to the `sum`. Also, increment the `count` by 1. 5. After the iteration, check if `count` is greater than 0 to avoid division by zero. 6. If `count` is greater than 0, calculate the arithmetic mean by dividing `sum` by `count`. 7. Return the arithmetic mean as the result.

Here's the code implementation in Python:

def find_arithmetic_mean(number):
    number_str = str(number)
    sum = 0
    count = 0

for digit in number_str:
        if digit == '2' or digit == '5':
            sum += int(digit)
            count += 1

if count > 0:
        arithmetic_mean = sum / count
        return arithmetic_mean
    else:
        return 0

Example Usage

Let's say we have the number 25345. We can use the `find_arithmetic_mean` function to find the arithmetic mean of the digits that are equal to 2 or 5:

number = 25345
arithmetic_mean = find_arithmetic_mean(number)
print(arithmetic_mean)

The output will be: ``` 3.5 ```

In this example, the arithmetic mean of the digits 2 and 5 in the number 25345 is 3.5.

I hope this helps! Let me know if you have any further questions.