Question

Битовая глубина цвета равна 32. Видеопамять делится на две страницы. Разрешающая способность дисплея 800x600.вычислить объем видеопамяти.

Answer 1

На каждой странице 800 * 600 = 1875 * 2^8 пикселей, так что на двух страницах 2 * 1875 * 2^8 = 1875 * 2^9 пикселей.

На кодирование цвета каждого пикселя отводится 32 бита = 4 байт = 2^2 байт.

На кодирование всех пикселей надо отвести 1875 * 2^9 * 2^2 байт = 1875 * 2^11 байт = 1875 * 2 Кб = 3750 Кб = 3,66 Мб
(1 Кб = 2^10 байт = 1024 байт, 1 Мб = 2^10 Кб)

Ответ. 3,66 Мб

Answer 2

Calculating the Video Memory Size

To calculate the video memory size, we need to consider the color depth and the resolution of the display.

The color depth, or bit depth, refers to the number of bits used to represent each pixel on the screen. In this case, the color depth is given as 32 bits.

The resolution of the display is given as 800x600 pixels.

To calculate the video memory size, we can use the following formula:

Video Memory Size = Color Depth * Resolution

Substituting the given values:

Video Memory Size = 32 bits * 800 pixels * 600 pixels

Now we can calculate the video memory size:

Video Memory Size = 32 bits * 480,000 pixels

Calculating the product:

Video Memory Size = 15,360,000 bits

To convert the video memory size to a more common unit, we can divide by 8 to get the size in bytes:

Video Memory Size = 15,360,000 bits / 8 = 1,920,000 bytes

Therefore, the video memory size is 1,920,000 bytes.

Please note that this calculation assumes a linear frame buffer, where each pixel occupies the specified number of bits. In practice, there may be additional overhead and memory requirements for storing other data structures and buffers.

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