Question

Что будет выведено на экран begin x:=1; if (x< >1) or (x>10) then y:=6 else; y:=0; writeln(y); end. А)1 В)2 С)0 Д)Y

Answer 1

X = 1;
(x<>1) or (x>10) ⇒ (1<>1) or (1>10) ⇒ False or False ⇒ False
y = 0
Ответ: С)0

Answer 2

Answer:

The code snippet provided is not syntactically correct. There is a syntax error in the `else` statement. The correct syntax should be `else y:=0;`.

Assuming the correct syntax, the code will assign the value 1 to the variable `x`. Then, it will check if `x` is less than 1 or greater than 10. Since `x` is equal to 1, the condition `(x<1) or (x>10)` will evaluate to false. Therefore, the code will execute the `else` block and assign the value 0 to the variable `y`. Finally, it will print the value of `y`, which is 0.

So, the correct answer is C) 0.

Please note that the code snippet provided is incomplete and may not run as expected due to the syntax error.