Question

Составить алгоритм на языке программирования , который выводит среднее арифметическое наибольшего и наименьшего из 20 элементов , имеющих значение из интервала [-10;10]

Answer 1

Pascal:
const n=20;
var a: array[1..n] of integer;
max, min, i: integer;
begin
max:=-11;
min:=11;
for i:=1 to n do begin
a[i]:=random(20)-10; {или readln(a[i]); если нужен конкретный ввод}
if a[i]>max then max:=a[i];
if a[i]<min then min:=a[i];
end;
writeln((max+min)/2);
end.

Answer 2

Algorithm for Finding the Average of the Largest and Smallest of 20 Elements

To create an algorithm in Python that calculates the average of the largest and smallest of 20 elements within the range [-10, 10], you can follow these steps:

1. Generate 20 Random Numbers within the Specified Range: - Use a random number generator to create a list of 20 elements with values in the range [-10, 10].

2. Find the Largest and Smallest Numbers: - Iterate through the list to find the largest and smallest numbers.

3. Calculate the Average: - Add the largest and smallest numbers together and divide the sum by 2 to find the average.

Here's a Python algorithm to achieve this:

import random

# Step 1: Generate 20 Random Numbers within the Specified Range
random_numbers = [random.randint(-10, 10) for _ in range(20)]

# Step 2: Find the Largest and Smallest Numbers
largest = max(random_numbers)
smallest = min(random_numbers)

# Step 3: Calculate the Average
average = (largest + smallest) / 2

print("Random Numbers:", random_numbers)
print("Largest Number:", largest)
print("Smallest Number:", smallest)
print("Average of Largest and Smallest:", average)

This algorithm uses Python's built-in functions to find the largest and smallest numbers and then calculates their average.

Please note that the algorithm provided is in Python, as it is a widely used and easy-to-understand language for such tasks. If you have a specific programming language in mind, I can tailor the algorithm accordingly.