Question

Задача 1. Получено сообщение, информационный объем которого равен 64 битам. чему равен этот объем в байтах? Задача 2. Объем информацинного сообщения 12582916 битов выразить в килобайтах и мегабайтах. Задача 3. Компьютер имеет оперативную память 1024 Мб. Количество соответствующих этой величине бит больше: 1) 10 000 000 000бит 2) 8 000 000 000бит 3) 6 000 000 000бит 4) 4 000 000 000бит Задача 4. У племени "чичевоков" в алфавите 56 букв и 8 цифр. Знаков препинания и арифметических знаков нет. Какое минимальное количество двоичных разрядов им необходимо для кодирования всех символов? Учтите, что слова надо отделять друг от друга! Задача 5. Сколько мегабайт информации содержит сообщение объемом 224 бит?

Answer 1

1) 8, 2) килобайт-1536, мегабайт-1.5 3) 1 (вроде) , 4) не знаю, 5) 2.097152 мегабайт

Answer 2

Task 1: Converting 64 bits to bytes

To convert the information volume of 64 bits to bytes, we need to divide the number of bits by 8, since there are 8 bits in a byte.

The calculation is as follows:

64 bits / 8 = 8 bytes

Therefore, the information volume of 64 bits is equal to 8 bytes. [[1]]

Task 2: Converting 12,582,916 bits to kilobytes and megabytes

To convert the information volume of 12,582,916 bits to kilobytes and megabytes, we need to divide the number of bits by the appropriate conversion factors.

1 kilobyte (KB) = 8,192 bits 1 megabyte (MB) = 8,388,608 bits

The calculations are as follows:

12,582,916 bits / 8,192 = 1,536.00 kilobytes (KB) 12,582,916 bits / 8,388,608 = 1.50 megabytes (MB)

Therefore, the information volume of 12,582,916 bits is equal to 1,536.00 kilobytes (KB) and 1.50 megabytes (MB). [[2]] [[3]]

Task 3: Determining the number of bits corresponding to 1024 MB of RAM

To determine the number of bits corresponding to 1024 MB of RAM, we need to multiply the number of megabytes by the conversion factor.

1 megabyte (MB) = 8,388,608 bits

The calculation is as follows:

1024 MB * 8,388,608 = 8,589,934,592 bits

Therefore, the number of bits corresponding to 1024 MB of RAM is 8,589,934,592 bits. [[4]]

Task 4: Calculating the minimum number of binary digits required to encode all symbols

To calculate the minimum number of binary digits required to encode all symbols in the "chichevokov" tribe's alphabet, we need to consider the number of characters in the alphabet.

The alphabet consists of 56 letters and 8 digits, without any punctuation or arithmetic signs.

To encode all symbols, we need to find the smallest power of 2 that is greater than or equal to the total number of symbols.

The calculation is as follows:

Total number of symbols = 56 letters + 8 digits = 64 symbols

The smallest power of 2 greater than or equal to 64 is 2^6 = 64.

Therefore, the minimum number of binary digits required to encode all symbols is 6 bits. [[5]]

Task 5: Converting 224 bits to megabytes

To convert the information volume of 224 bits to megabytes, we need to divide the number of bits by the appropriate conversion factor.

1 megabyte (MB) = 8,388,608 bits

The calculation is as follows:

224 bits / 8,388,608 = 0.0000267 megabytes (MB)

Therefore, the information volume of 224 bits is equal to 0.0000267 megabytes (MB). [[6]]