Question

Даны два действительных различных числа х и у. Заменить меньшее из этих двух чисел и полусуммой,а большее их утроенной полуразность?

Answer 1

var i,jx,y:longint;

begin

read(x,y):

i:=x;

j:=y

if x<y then begin x:= (i+j) div 2; y:= 3*((i+y)div2);

if y<x then begin y:= (i+j) div 2; x:= 3*((i+y)div2);

writeln(x,' ',y);

end.

Answer 2

var
x, y : real;
begin
readln (x, y);
if x < y then
begin
x := (x + y) / 2;
y := 6 * abs (x - y); 
end
else
begin
y := (y + x) / 2;
x := 6 * abs (y - x);
end;
writeln (x, ' ', y);
readln;
end.

Answer 3

Solving the Mathematical Problem

To solve the given problem, we need to replace the smaller of the two different real numbers, x and y, with their half-sum, and the larger one with three times the half-difference.

Let's denote the two different real numbers as x and y.

1. Identify the Smaller and Larger Numbers: - Let's assume x is the smaller number and y is the larger number.

2. Calculate the Half-Sum and Half-Difference: - The half-sum of x and y is given by: (x + y) / 2 - The half-difference of x and y is given by: |x - y| / 2

3. Replace the Numbers: - Replace the smaller number (x) with the half-sum: (x + y) / 2 - Replace the larger number (y) with three times the half-difference: 3 * |x - y| / 2

Applying the Formulas

Let's apply the formulas to solve the problem:

- The half-sum of x and y: (x + y) / 2- The half-difference of x and y: |x - y| / 2- Replace the smaller number (x) with the half-sum: (x + y) / 2 - Replace the larger number (y) with three times the half-difference: 3 * |x - y| / 2

Therefore, the solution to the given problem is to replace the smaller of the two numbers with their half-sum, and the larger one with three times the half-difference.