Question

Вычислить сумму n ∑ (-1)n / (2i) i=1 Помогите написать решение в паскале

Answer 1

Var
  s : Real;
  i,n : Integer;
Begin
  s:=0;
  Readln(n);
  For i:=1 to n do s:=s-n/(2*i);
end.

Answer 2

Calculating the Sum of n Terms

To calculate the sum of n terms in the series ∑(-1)^n / (2i) from i=1 to n, we can use the following steps:

1. Determine the Value of n: - First, we need to know the value of n to calculate the sum of n terms.

2. Calculate the Sum: - Once we have the value of n, we can use it to calculate the sum of n terms in the given series.

Let's proceed with the calculation.

Solution in Pascal

```pascal program SumOfNTerms; var n, i: integer; sum: real; begin // Input the value of n write('Enter the value of n: '); readln(n); // Initialize sum sum := 0; // Calculate the sum of n terms for i := 1 to n do begin sum := sum + power(-1, i) / (2 * i); end; // Output the sum writeln('The sum of ', n, ' terms is: ', sum:0:2); end. ```

This Pascal program calculates the sum of n terms in the given series ∑(-1)^n / (2i) from i=1 to n. You can input the value of n, and the program will output the sum of n terms.

I hope this helps! Let me know if you need further assistance.