Question

Определите, что будет выведено на экран после выполнения фрагмента программы: x:=0; y:=5; While y больше 0 do begin y:=y - 2; x:=x + y; end; writeln (‘x=’, x); Ответ: х=5 3 х=3 5

Answer 1

Ответ будет 3, т.к. по алгоритму будет 0+3=3; 3+1=4; 4+(-1)=3;

Answer 2

Code Fragment Analysis

Let's analyze the given code fragment step by step to determine what will be displayed on the screen after its execution:

1. Initialize variables: - `x` is assigned the value of 0. - `y` is assigned the value of 5.

2. Enter the `while` loop: - The condition `y > 0` is evaluated. - Since `y` is initially 5, the condition is true, and the loop is entered.

3. Loop iteration 1: - `y` is decremented by 2, resulting in a new value of 3. - `x` is incremented by the current value of `y`, which is 3. So `x` becomes 3.

4. Loop iteration 2: - `y` is decremented by 2 again, resulting in a new value of 1. - `x` is incremented by the current value of `y`, which is 1. So `x` becomes 4.

5. Loop iteration 3: - `y` is decremented by 2 again, resulting in a new value of -1. - Since `y` is now less than or equal to 0, the loop condition is false, and the loop is exited.

6. Output the result: - The value of `x` is printed to the screen using the `writeln` statement.

Output Result

Based on the analysis of the code fragment, the value of `x` will be 4 when it is displayed on the screen.

Please let me know if you need any further assistance!