Question

A:=1; b:=1; while a<=32 do a:=a*2; b:=b*a; write (b)

Answer 1

Ответ:

64

полагаю был вопрос что выведется на экран

Answer 2

The code you've provided is written in a pseudo-code or a code-like syntax. It appears to be a simple loop that initializes two variables a and b to 1 and then repeatedly doubles the value of a and multiplies b by the new value of a until a is no longer less than or equal to 32. At each step, it writes the value of b.

Here's a step-by-step breakdown of what the code does:

1. Initialize a to 1.
2. Initialize b to 1.
3. Enter a while loop that continues as long as a is less than or equal to 32.
4. Inside the loop: a. Double the value of a (a := a * 2). b. Multiply b by the new value of a (b := b * a). c. Write the current value of b to some output (e.g., a console or a file).
5. Repeat the loop until a is greater than 32.

This code calculates the product of all powers of 2 from 2^1 to 2^32 and writes the result of each multiplication. The output would be a sequence of numbers, where each number is the result of multiplying the previous number by the next power of 2.

The final output would be a sequence of numbers like this:

1 2 8 64 1024 32768 ... and so on, with each number being the product of the previous number and the next power of 2.