Question

Помогите с паскалем! Нужно вычислить сумму отрицательных элементов одномерного массива А с длинной N стоящий на чётных местах

Answer 1

Const
   N = 13;
Var
   A:array[1..N] of integer;
   i:integer;
   S:real;
Begin
Randomize;
Write('Исходный массив:');
For i:= 1 to N do
    Begin
    A[i]:=random(2*N+1)-N;
    Write(' ',A[i]);
    if (i mod 2 = 0)and(A[i] < 0) then S:=S+A[i]
    End;
WriteLn;
WriteLn('S = ',S);
ReadLn;
End.

Answer 2

Calculating the Sum of Negative Elements in an Array

To calculate the sum of the negative elements of a one-dimensional array A with a length of N standing at even positions, you can use the following approach:

1. Initialize the Array: Start by initializing the one-dimensional array A with the given length N.

2. Identify Negative Elements at Even Positions: Iterate through the array and identify the negative elements at even positions.

3. Calculate the Sum: Sum up the identified negative elements at even positions to obtain the final result.

Here's a simple example of how you can achieve this in pseudocode:

var
  A: array[1..N] of integer; // Initialize the array A with length N
  sum: integer; // Variable to store the sum of negative elements at even positions
  i: integer; // Loop variable

begin
  sum := 0; // Initialize the sum to 0
  for i := 2 to N step 2 do // Iterate through even positions of the array
  begin
    if A[i] < 0 then // Check if the element at the even position is negative
      sum := sum + A[i]; // Add the negative element to the sum
  end;
  // The variable 'sum' now contains the sum of negative elements at even positions in the array A
end.

This pseudocode outlines the basic steps to calculate the sum of negative elements at even positions in a one-dimensional array using Pascal.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.