Question

Q=int(input()) w=1a=0for i in range(1, q): print(i, end=" ") print(q)for i in range(q-1, 0, -1): print(i, end=" ")Вывод :(при q=4)1 2 3 43 2 1а нужен1 2 3 4 3 2 1

Answer 1

Ответ:

q = int(input())

a = []

for i in range(1, q+1):

 a.append(i)

b = []

for _ in a:

 b.append(_)

a.pop()

a = list(reversed(a))

b += a

print(*b)

P.S. Если помог, отметьте лучшим решением:)

Объяснение:

Answer 2

Ответ:

так а что должен делать код...

Объяснение:

Answer 3

It looks like you want to print a pattern of numbers in Python based on the input q. Your current code has some issues, so I'll provide a corrected version of the code to achieve the desired output:

pythonCopy code
q = int(input())

# Print numbers from 1 to q
for i in range(1, q + 1):
    print(i, end=" ")

# Print numbers from q-1 down to 1
for i in range(q - 1, 0, -1):
    print(i, end=" ")

With this code, when q is set to 4, it will print the pattern as follows:

Copy code
1 2 3 4 3 2 1

The changes made include:

1. Adjusting the range in the first loop to include q itself.
2. Adding spaces between the numbers in the output by using end=" ".
3. Correcting the second loop to count down from q-1 to 1.