Question

Write an algorithm that takes an list and moves all of the zeros to the end, preserving the order of the other elements. move_zeros([False,1,0,1,2,0,1,3,"a"]) # returns[False,1,1,2,1,3,"a",0,0] For test exemples: [1,2,0,1,0,1,0,3,0,1] [9,0.0,0,9,1,2,0,1,0,1,0.0,3,0,1,9,0,0,0,0,9] ["a",0,0,"b","c","d",0,1,0,1,0,3,0,1,9,0,0,0,0,9] ["a",0,0,"b",None,"c","d",0,1,False,0,1,0,3,[],0,1,9,0,0,{},0,0,9] [0,1,None,2,False,1,0] ["a","b"] ["a"] [0,0] [0] [False] [] On Python

Answer 1

arr = input("Enter the array separated by a space: ").split()

count = 0

print(arr)

def sort(arr, count = 0):

"""The function sorts the array using the bubble algorithm"""

point = len(arr)

while True:

 if count == point - 1:

  count = 0

  point -= 1

 elif point == 1:

  break

 if arr[count] == "0":

  arr[count + 1],arr[count] = arr[count], arr[count + 1]

 

 count += 1

return arr

sort(arr)

print(arr)

Answer 2

You can achieve this by iterating through the list and moving all the zeros to the end while preserving the order of the other elements. Here's a Python algorithm to do that:

pythonCopy code
def move_zeros(arr):
    non_zero_count = 0  # Count of non-zero elements
    
    # Iterate through the list and move non-zero elements to the front
    for i in range(len(arr)):
        if arr[i] != 0:
            arr[non_zero_count], arr[i] = arr[i], arr[non_zero_count]
            non_zero_count += 1
    
    # Fill the remaining positions with zeros
    while non_zero_count < len(arr):
        arr[non_zero_count] = 0
        non_zero_count += 1
    
    return arr

# Test cases
print(move_zeros([False, 1, 0, 1, 2, 0, 1, 3, "a"]))  # Output: [False, 1, 1, 2, 1, 3, 'a', 0, 0]
print(move_zeros([1, 2, 0, 1, 0, 1, 0, 3, 0, 1]))
print(move_zeros([9, 0.0, 0, 9, 1, 2, 0, 1, 0, 1, 0.0, 3, 0, 1, 9, 0, 0, 0, 0, 9]))
print(move_zeros(["a", 0, 0, "b", "c", "d", 0, 1, 0, 1, 0, 3, 0, 1, 9, 0, 0, 0, 0, 9]))
# Add more test cases as needed

This algorithm maintains two pointers - non_zero_count and i. non_zero_count keeps track of the position where the next non-zero element should be placed, and i iterates through the list. When a non-zero element is encountered at index i, it is swapped with the element at index non_zero_count, effectively moving all non-zero elements to the front. Finally, any remaining positions in the list are filled with zeros to complete the process.