Question

Решите программу Program test2; var i,s:integer; begin s:=0; for i:=4 to 10 do s:=s+i; writeln(s); S:=s*i; writeln(s); end.

Answer 1

Смотри приложенный файл

Answer 2

To understand and solve the program, let's go through it step by step:

1. Initialize variables: The program declares two integer variables, "i" and "s."

2. Initialize s: The variable "s" is set to 0.

3. For loop: The program executes a for loop with "i" ranging from 4 to 10 (inclusive).

4. Accumulate sum: Inside the loop, the variable "s" is incremented by the value of "i" in each iteration. So, after the loop, "s" will hold the sum of numbers from 4 to 10.

5. Write the first sum: The program writes the value of "s" after the for loop execution, which will be the sum of numbers from 4 to 10.

6. Multiply s by i: The program multiplies "s" by the value of "i" (which will be 10 after the loop) and assigns the result back to "s."

7. Write the second sum: Finally, the program writes the updated value of "s," which is the sum of numbers from 4 to 10 multiplied by 10.

Let's write down the output of each step:

cssCopy code
s := 0; (Initialization of s)
i := 4; (Start of the loop)
s := 0 + 4; (Sum so far: 4)
i := 5;
s := 4 + 5; (Sum so far: 9)
i := 6;
s := 9 + 6; (Sum so far: 15)
i := 7;
s := 15 + 7; (Sum so far: 22)
i := 8;
s := 22 + 8; (Sum so far: 30)
i := 9;
s := 30 + 9; (Sum so far: 39)
i := 10;
s := 39 + 10; (Sum so far: 49)
writeln(s); -> This will output 49 (Sum of numbers from 4 to 10)

S := 49 * 10; (s after the loop is multiplied by 10)
writeln(s); -> This will output 490 (Sum of numbers from 4 to 10 multiplied by 10)

So, the final output of the program will be:

Copy code
49
490