Question

P=2\3*4\5*6\7....2n 2n+1 написать на языке C++

Answer 1

#include <iostream>

using namespace std;

int main(){

  cout << "Enter n: ";

  int n;

  cin >> n;

  double p = 1;

  for(int i = 2; i<n; i++){

      p *= ((double)i)/(i+1.0);

  }

  cout << ''Result is: " << p << endl;

}

Как-то так, программу не компилировал, могут  быть незначительные синтаксические ошибки, но основной алгоритм такой.

Answer 2

To calculate the product P of the given sequence P = 2/3 * 4/5 * 6/7 * ... * (2n) / (2n+1) in C++, you can use a simple loop to iterate over the terms and accumulate the product. Here's a C++ code snippet to calculate the value of P for a given n:

cppCopy code
#include <iostream>

double calculateProduct(int n) {
    double product = 1.0;
    
    for (int i = 1; i <= n; i++) {
        double numerator = 2 * i;
        double denominator = 2 * i + 1;
        product *= numerator / denominator;
    }
    
    return product;
}

int main() {
    int n;
    std::cout << "Enter the value of n: ";
    std::cin >> n;

    double result = calculateProduct(n);
    std::cout << "The product P is: " << result << std::endl;

    return 0;
}

Copy and paste this code into a C++ compiler, and it will prompt you to enter the value of n. After entering the value, it will calculate and display the product P as per the given sequence.