Question

Массив задается, а затем меняется: for i := 1 to 10 do a[i] := 11 - i; for i := 10 downto 2 do begin tmp := a[i - 1]; a[i - 1] := a[i]; a[i] := tmp; end; Как выглядит массив после выполнения программы? 1)10, 9, 8, 7, 6, 5, 4, 3, 2, 1 2)9, 10, 7, 8, 5, 6, 3, 4, 1, 2 3)1, 2, 3, 4, 5, 6, 7, 8, 9, 10 4)2, 1, 4, 3, 6, 5, 8, 7, 10, 9 5)2, 3, 4, 5, 6, 7, 8, 9, 10, 1 6)1, 10, 9, 8, 7, 6, 5, 4, 3, 2

Answer 1

6) 1, 10, 9, 8, 7, 6, 5, 4, 3, 2

Вот полная программа:
var i,tmp: integer;
a: array[1..10] of integer;
begin
for i := 1 to 10 do
a[i] := 11 - i;
for i := 10 downto 2 do begin
tmp := a[i - 1];
a[i - 1] := a[i];
a[i] := tmp;
end;
for i:=1 to 10 do writeln(a[i]);
end.

Answer 2

To determine the resulting array after executing the given code, let's step through the code and track the changes:

1. The initial array is set using the first loop:

   lessCopy code
   for i := 1 to 10 do a[i] := 11 - i;
   

   The array becomes: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1].

2. The second loop is executed:

   lessCopy code
   for i := 10 downto 2 do begin
       tmp := a[i - 1];
       a[i - 1] := a[i];
       a[i] := tmp;
   end;
   

   In this loop, the value of each element from index 2 to 10 is swapped with the value of the previous element. The value of a[1] remains unchanged.

   After this loop, the array becomes: [9, 10, 7, 8, 5, 6, 3, 4, 1, 2].

So, the correct answer is: Option 2) [9, 10, 7, 8, 5, 6, 3, 4, 1, 2].