Question

1010101011(2) - Х(20)

Answer 1

$Otvet:$

$1010101011_{2} = 1E3_{20}$

$Obyasnenie:$

$1010101011_{2}$ ⇒ $X_{10}$

$1010101011_{2} = 1*2^{9} +0*2^{8} +1*2^{7}+0*2^{6}+1*2^{5}+0*2^{4}+1*2^{3}+0*2^{2}+1*2^{1}+1*1 = 683_{10}$

$683_{10}$⇒$X_{20}$

$\frac{683}{20} = 34; Ostatok: 3$

$\frac{34}{20} = 1; Ostatok: 14, 14=E$

$\frac{1}{20} = 1; Ostatok: 1$

$683_{10}$ ⇒ $1E3_{20}$

Answer 2

To subtract a number in base 20 from a number in base 2, we need to convert both numbers to a common base. Let's convert the base 2 number to base 20.

The base 2 number 1010101011 can be converted to base 10 as follows:

1 * 2^9 + 0 * 2^8 + 1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 1 * 2^0 = 683

Now, let's convert this number from base 10 to base 20:

683 divided by 20 equals 34 with a remainder of 3. 34 divided by 20 equals 1 with a remainder of 14. 1 divided by 20 equals 0 with a remainder of 1.

Therefore, the number 683 in base 10 is equal to 1E3 in base 20.

Now we can subtract the base 20 number from the base 20 number:

1E3 (base 20) - Х (base 20) = ?

Since we don't know the specific value of Х, we cannot determine the result of the subtraction. Please provide the value of Х in base 20 for a specific result.