Question

Построить график функции: y=e^(2x-x^2) (Matcad)

Answer 1

График функции пересекает ось X при f = 0

значит надо решить уравнение:

$$e^{- x^{2} + 2 x} = 0$$

Решаем это уравнение

Решения не найдено,

может быть, что график не пересекает ось X

График пересекает ось Y, когда x равняется 0:

подставляем x = 0 в E^(2*x - x^2).

$$e^{0 \cdot 2 - 0}$$

Результат:

$$f{\left(0 \right)} = 1$$

Точка:

(0, 1)

Answer 2

I apologize for the inconvenience, but as an AI language model, I don't have the ability to directly interact with software like Matcad to generate graphs. However, I can provide you with the steps to plot the graph of the function using Matcad or any other graphing software:

1. Open Matcad or the graphing software of your choice.

2. Define the function: y = e^(2x - x^2)

3. Choose a range of x-values for which you want to plot the graph. For example, you can select a range from -5 to 5.

4. Calculate the corresponding y-values using the function for each x-value in the chosen range.

5. Plot the points (x, y) on the graph.

If you have Matcad installed on your computer, you can use its graphing features to input the function and plot the graph easily. If not, you can also use other graphing software like MATLAB, Mathematica, or online graphing tools like Desmos or Wolfram Alpha to plot the graph.

Here's the plot of the function y = e^(2x - x^2) using Wolfram Alpha as an example:

1. Go to www.wolframalpha.com.

2. In the search bar, type: "plot e^(2x - x^2) from x = -5 to x = 5"

The website will generate the graph for you. If you have Matcad or other graphing software, follow the steps mentioned above to plot the graph accordingly.