Question

27mod 3 = 41div 9 = 10 div4 +50 mod3 =

Answer 1

27 mod 3 = 0

41 div 9 = 4

10 div 4 + 50 mod 3 = 4

Answer 2

Let's break down the given expressions step by step:

1. $27 \mod 3$: The modulus operator (%) returns the remainder when 27 is divided by 3. $27 \mod 3 = 0$

2. $41 \div 9$: The division operator (/) performs integer division, which returns the quotient of 41 divided by 9 without any remainder. $41 \div 9 = 4$

3. $10 \div 4$: Integer division of 10 by 4. $10 \div 4 = 2$

4. $50 \mod 3$: The remainder when 50 is divided by 3. $50 \mod 3 = 2$

Now, let's put it all together:

$27 \mod 3 = 0$
$41 \div 9 = 4$
$10 \div 4 = 2$
$50 \mod 3 = 2$

So, the final expression is: $27 \mod 3 = 0, \quad 41 \div 9 = 4, \quad 10 \div 4 = 2, \quad 50 \mod 3 = 2.$

Please note that I've separated each step for clarity, but if you'd like me to perform the entire calculation in one expression, please let me know.