Question

What is the output of the following code?x=5 while x>=0: print (x) ifx=="1": print ("Blast off!") x=x-1*​

Answer 1

Ответ:

5 4 3 2 1 Blast off! 0

Объяснение:

x = 5

x >= 0 ? - Yes, so we print 5.   x == 1? No.  x = x - 1 = 5 - 1 = 4.

x = 4

x >= 0 ? - Yes, so we print 4. x == 1? No. x = x - 1 = 4 - 1 = 3

x = 3

x >= 0 ? - Yes, so we print 3. x == 1? No. x = 3 - 1 = 3 - 1 = 2

x = 2

x >= 0 ? - Yes, so we print 2. x == 1? No. x = x - 1 = 2 - 1 = 1

x = 1

x >= 0 ? - Yes, so we print 1. x == 1? Yes, so we print "Blast off!". x = 1=x - 1 = 1 - 1 = 0

x = 0

x >= 0 ? - Yes, so we print 0. x == 1? No. x = x - 1 = 0 - 1 = -1

x = -1

x >= 0? - No

Answer 2

The code you've provided seems to have a few syntax errors, but I'll help you correct them and provide the expected output.

Here's the corrected code:

pythonCopy code
x = 5
while x >= 0:
    print(x)
    if x == 1:
        print("Blast off!")
    x = x - 1

Now, let's go through the code step by step:

1. x is initialized to 5.
2. The while loop runs as long as x is greater than or equal to 0.
3. Inside the loop, it prints the value of x.
4. It checks if x is equal to 1. If it is, it prints "Blast off!"
5. Regardless of the condition, x is decremented by 1 in each iteration.

Output:

vbnetCopy code
5
4
3
2
1
Blast off!

Explanation: The loop iterates through the values of x from 5 down to 1. When x becomes 1, it prints "Blast off!" alongside the value. Then, the loop continues with x being decremented to 0, and the loop stops because the condition x >= 0 is no longer satisfied.