Question

a := 13; b := 17; x := b; if a>b then x := a-b else if x>a then x := b-a else x := a-b; writeln (x);

Answer 1

Ответ:

Программа выведет число 4

Объяснение:

Answer 2

The given code is written in a pseudo-code or programming language style and calculates the value of variable x based on the conditions provided. Let's break down the code step by step:

pseudoCopy code
a := 13;
b := 17;
x := b;

if a > b then
    x := a - b
else
    if x > a then
        x := b - a
    else
        x := a - b;

writeln(x);

Here's what the code does:

1. a is assigned the value 13.
2. b is assigned the value 17.
3. x is assigned the value of b, which is 17.

Now, let's go through the conditions:

• Since a (which is 13) is not greater than b (which is 17), the code goes to the else block of the first if statement.

• Now, the inner if statement checks if x (which is 17) is greater than a (which is 13). This condition is true, so x is updated to the result of b - a, which is 17 - 13 = 4.

• Finally, the value of x is 4, and writeln(x) prints the value 4 to the output.

So, the output of the given code is:

Copy code
4